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Home » DIY Home Update: How to Use Drywall Anchors Without Breaking a Sweat - Silent Sales Machine

DIY Home Update: How to Use Drywall Anchors Without Breaking a Sweat - Silent Sales Machine

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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C = \pi \cdot ext{diameter} = \pi \cdot 8\sqrt{2} = 8\sqrt{2}\pi ext...
Thus, the circumference of the circle is $ oxed{8\sqrt{2}\pi} $ cm.
Question: The area of an equilateral triangle is $ 25\sqrt{3} $ cmÂ²....
Solution: The area $ A $ of an equilateral triangle with side length $...
A = rac{\sqrt{3}}{4}s^2
Set this equal to the given area:
rac{\sqrt{3}}{4}s^2 = 25\sqrt{3}
Divide both sides by $ \sqrt{3} $:
rac{1}{4}s^2 = 25 \Rightarrow s^2 = 100 \Rightarrow s = 10 ext{ cm}
The new side length is $ s + 4 = 14 $ cm. Compute the new area:

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باستخدام متطابقة الزاوية المزدوجة، $\cos 2z = 1 - 2\sin^2 z$, تصبح الم...
- 2\sin^2 z = \sin z \implies 2\sin^2 z + \sin z - 1 = 0
لنفترض $u = \sin z$, إذن:
2u^2 + u - 1 = 0 \implies u = \frac{-1 \pm \sqrt{1 + 8}}{4} = \frac{-1...
إذن، $u = \frac{1}{2}$ أو $u = -1$.
لـ $\sin z = \frac{1}{2}$:
z = 30^\circ \quad \text{أو} \quad z = 150^\circ
لـ $\sin z = -1$:
z = 270^\circ
وبالتالي، الحلول في $[0^\circ, 360^\circ]$ هي:

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