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📌 We solve \( e^{-0.05t} = 0.25 \).
📌 -0.05t = \ln(0.25) = \ln(1/4) = -\ln 4 \approx -1.3863
📌 t = \frac{1.3863}{0.05} = 27.726 \approx 28 \text{ years}
📌 Thus, it takes about 28 years.
📌 #### C
📌 A STEM advocate designs a series of workshops where each workshop engages \( n \) students, and participation grows by 20% per term. After how many terms will the number of participants exceed 5 times the initial number?
📌 A. 6
📌 B. 7