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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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2r + 2 = (3 + \sqrt{5})r - 3 - \sqrt{5}
2r - (3 + \sqrt{5})r + 2 + 3 + \sqrt{5} = 0
r = rac{5 + \sqrt{5}}{1 + \sqrt{5}}
Rationalize:
r = rac{(5 + \sqrt{5})(1 - \sqrt{5})}{(1 + \sqrt{5})(1 - \sqrt{5})} =...
Case 2:** \( rac{r+1}{r-1} = rac{3 - \sqrt{5}}{2} \)
Similarly:
2(r+1) = (3 - \sqrt{5})(r - 1)
2r + 2 = (3 - \sqrt{5})r - (3 - \sqrt{5})
2r + 2 = (3 - \sqrt{5})r - 3 + \sqrt{5}

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