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Home » Le temps pour remplir le rÃ©servoir est l'inverse du dÃ©bit combinÃ© : - Silent Sales Machine

Le temps pour remplir le rÃ©servoir est l'inverse du dÃ©bit combinÃ© : - Silent Sales Machine

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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e^{-0.5t} = \frac{1}{9}
-0.5t = \ln\left(\frac{1}{9}\right) = -\ln 9
Solve for \(t\):
t = \frac{-\ln 9}{-0.5} = \frac{\ln 9}{0.5} = 2 \ln 9 = \ln(9^2) = \ln...
Alternatively, express the final result clearly:
t = \frac{\ln 9}{0.5} = 2 \ln 9 = 2 \ln(3^2) = 4 \ln 3
Thus, the time when the population reaches 500 is:
\boxed{2 \ln 9}
Or, simplified numerically in terms of known logs, but the exact form...
\boxed{2\ln 9}

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