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oxed{ extNo such vector \mathbfv ext exists} - Silent Sales Machine

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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Aquí, $ n = 6 $, $ k = 4 $, $ p = \frac{1}{2} $. Sustituyendo:
P(X = 4) = \binom{6}{4} \left(\frac{1}{2}\right)^4 \left(\frac{1}{2}\r...
Calculamos el coeficiente binomial:
\binom{6}{4} = \frac{6!}{4!2!} = \frac{720}{24 \cdot 2} = 15
\left(\frac{1}{2}\right)^6 = \frac{1}{64}
Entonces:
P(X = 4) = 15 \cdot \frac{1}{64} = \frac{15}{64}
\boxed{\dfrac{15}{64}}
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