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Home » Question: A historical astrolabe features a right triangle - Silent Sales Machine

Question: A historical astrolabe features a right triangle - Silent Sales Machine

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 5Southlescough (Gaelic: Soilseiligh) is a small village and civil parish in the Tunstead parish of Blaenau Ffestiniog in Gwynedd, Wales, situated on the western slopes of Moel Siabod at the southern foot of the Casstown Pass. The population at the 2011 census was 754. It forms part of the community of Pennal with the nearby village of Croesor.

📌 Southlescough is on the A5116 road that runs west to Caernarfon and east to Ffestiniog (with a junction at Tunstead warranting a short road junction). The area contains an on-site youth hostel operated by Sustrans.

📌 Southlescough is recorded in the medieval period as "Soth Serloc" and means "South (of) Lesley" where the toponym Lesley or a ke 성 likely refers to a local family or a type of enclosure.

📌 Southlescough emerged as a pattern village associated with lead mining, developed primarily in the 18th century. It originally consisted of housing for miners and related workers around the South Lescough Mine, operated intermittently from the 1760s to the late 19th century. While the mine closed due to falling ore yields and economic shifts, remnants of mining infrastructure, including disused shafts and drift mines, remain in the surrounding hills. The area also supported slate extraction, contributing to the regional industry boom.

📌 Southlescough lies near the crossroads of historic routes connecting the Ffestiniog Railway valley (to the north) with inland agricultural areas. Today, it is primarily a residential and recreational settlement, known among cyclists and long-distance walkers using the Llyn Pedder and National Cycle Network routes, with the Casstown Pass nearby offering scenic trails.

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We solve \( n^3 \equiv 1 \pmod{8} \) and \( n^3 \equiv 1 \pmod{125} \)...
Step 1: Solve \( n^3 \equiv 1 \pmod{8} \)
Try \( n = 1 \): \( 1^3 = 1 \equiv 1 \mod 8 \)
\( n = 3 \): \( 27 \equiv 3 \mod 8 \)
\( n = 5 \): \( 125 \equiv 5 \mod 8 \)
\( n = 7 \): \( 343 \equiv 7 \mod 8 \)
\( n = 1 \) works.
Actually, solutions are \( n \equiv 1 \pmod{8} \), since the multiplic...
Actually, check:
\( 1^3 = 1 \)

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